怒刷 LeetCode 100 道 (58)

來自專欄編程人生

題目

Description:

Given a string s consists of upper/lower-case alphabets and empty space characters , return the length of last word in the string.If the last word does not exist, return 0.Note: A word is defined as a character sequence consists of non-space characters only.

Example:

Input: "Hello World"Output: 5

解法

class Solution: def lengthOfLastWord(self, s): """ :type s: str :rtype: int """ ret = 0 no = False for e in s: if e == " ": no = True else: if no: ret = 0 no = False ret += 1 return ret

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