python如何生成一個日期列表?

02-10

比如輸入起止日期就能生成這段日期的一個列表def datelist(8,3,10,9) return L=[8月3日，8月4日，...，10月9日]

建議用pandas庫：

import pandas as pd from datetime import datetime def datelist(beginDate, endDate): # beginDate, endDate是形如『20160601』的字元串或datetime格式 date_l=[datetime.strftime(x,%Y-%m-%d) for x in list(pd.date_range(start=beginDate, end=endDate))] return date_l

import datetime


def datelist(start, end):

    start_date = datetime.date(*start)

    end_date = datetime.date(*end)
    result = []

    curr_date = start_date

    while curr_date != end_date:

        result.append("%04d%02d%02d" % (curr_date.year, curr_date.month, curr_date.day))

        curr_date += datetime.timedelta(1)

    result.append("%04d%02d%02d" % (curr_date.year, curr_date.month, curr_date.day))

    return result

if __name__ == "__main__": print datelist((2014, 7, 28), (2014, 8, 3))

import datetime


def dateRange(start, end, step=1, format="%Y-%m-%d"):

    strptime, strftime = datetime.datetime.strptime, datetime.datetime.strftime

    days = (strptime(end, format) - strptime(start, format)).days

    return [strftime(strptime(start, format) + datetime.timedelta(i), format) for i in xrange(0, days, step)]

if __name__ == __main__: print dateRange("2017-01-01", "2017-01-03") # ["2017-01-01", "2017-01-02"]

import time

def dateRange(bgn, end): fmt = %Y-%m-%d bgn = int(time.mktime(time.strptime(bgn,fmt))) end = int(time.mktime(time.strptime(end,fmt))) return [time.strftime(fmt,time.localtime(i)) for i in range(bgn,end+1,3600*24)]