Python將list連續元素和非連續元素分開轉換為指定字元串

貼吧網友提問

http://tieba.baidu.com/p/3730249293

已知一個由純數字(順序由小按大排序)元素組成的列表，比如

li=[1,2,3,4,5,7,8,15,20,21,22,23,24,28]

寫一個函數，讓它返回如下的字元串

str=1~5,7~8,15,20~24,28

若數字連續，中間部分用 ~ 省略。

#!/usr/bin/env python# coding:utf-8#Author: 黃哥python培訓 qq:1465376564"""黃哥python遠程視頻培訓班https://github.com/pythonpeixun/article/blob/master/index.md黃哥python培訓試看視頻播放地址https://github.com/pythonpeixun/article/blob/master/python_shiping.md諮詢qq:1465376564""" def continuous_str(lst): j = 0 str1 = for i, item in enumerate(lst): if i > 0: if lst[i] != lst[i-1] + 1: tmp = lst[j:i] if len(tmp) == 1: str1 += str(tmp[0]) + , else: str1 += str(tmp[0]) + "~" + str(tmp[-1]) + , j = i tmp2 = lst[j:] if len(tmp2) == 1: str1 += str(tmp2[0]) + , else: str1 += str(tmp2[0]) + "~" + str(tmp2[-1]) + , return str1[:-1] lst = [1, 2, 3, 4, 5, 7, 8, 15, 20, 21, 22, 23, 24, 28]print continuous_str(lst)

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